Question

Potassium Chlorate on strong heating in the presence of Manganese dioxide catalyst form potassium chloride liberating oxygen. Calculate the volume of Oxygen liberated at STP, When 36.75g of Potassium Chlorate is completely decomposed.​

Answer 1

Answer:

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Explanation:

When potassium chlorate (KClO3) is heated in the presence of manganese dioxide catalyst, it decomposes to form potassium chloride and oxygen gas. 

The balanced chemical equation is

2KClO3→Δ2KCl+3O2

Answer 2

Answer:

When potassium chlorate (KClO3) is heated in the presence of manganese dioxide catalyst, it decomposes to form potassium chloride and oxygen gas.

The balanced chemical equation is

2KClO3→Δ2KCl+3O2