Potassium in chlorine react to form a compound explain on the basis of electronic concept first oxidation second reduction third oxidizing agent for reducing agent
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2K + Cl2 —> 2KCl
Oxidation number for K and Cl will be 0 as they are elements. In KCl, oxidation number for K will be +1 as it donates an electron, and for Cl it will be -1, as it receives an electon.
(a) Oxidation-
K is getting oxidized.
As,
0—> +1
(b)Reduction
Cl is getting reduced.
As,
0—> -1
(c)Oxidizing agent
Cl is the oxidizing agent as it brings about oxidation in K.
(d)Reducing agent.
K is the reducing agent as it brings about reduction in Cl.
Oxidation number for K and Cl will be 0 as they are elements. In KCl, oxidation number for K will be +1 as it donates an electron, and for Cl it will be -1, as it receives an electon.
(a) Oxidation-
K is getting oxidized.
As,
0—> +1
(b)Reduction
Cl is getting reduced.
As,
0—> -1
(c)Oxidizing agent
Cl is the oxidizing agent as it brings about oxidation in K.
(d)Reducing agent.
K is the reducing agent as it brings about reduction in Cl.
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