Question

potato kg 4 and onion 1 kg 50 paisa and garlic kg 25 paisa how we buy 10 kg in 10 rupees.. please answer..​

Answer 1

Given:

1 kg Potato = 4Rs

1 Kg Onion = 0.5Rs

1 Kg Garlic = 0.25 Rs

Total Weight = 10Kg

Total Cash = 10Rs

To Find:

How much of each vegetables should be bought.

Solution:

Let amount of Potato bought = P Kg

Let amount of Onion bought = N Kg

Let amount of Garlic bought = G Kg

• P + N + G = 10
• 4P + 0.5N + 0.25G = 10

Each terms in these two expressions must be a wholle number.

• 0.5N should be whole number = > N is an even number.
• N can be 0, 2, 4, 6, 8, 10.

• 4P < 10
• P can be 0, 1, 2.

• 0.25G should be a whole number :
• G is a multiple of 4 : 0, 4, 8.

Let P = 1 ,

• N + G = 9
• 0.5N + 0.5G = 0.5x9 = 4.5
• 0.5N + 0.25G = 6

Gives G as a negative number. Hence take P = 2

• N + G = 8
• 0.5N + 0.5G = 4
• 0.5N + 0.25G = 2
• 0.25G = 2
• G = 8

Therefore N = 0.

Amount of Potato bought is 2Kg, amount of Oninon bought is 0Kg and amount of Garlic bought is 8Kg.

Answer 2

Answer:

Step-by-step explanation:

1 kg Potato = 4Rs

1 Kg Onion = 0.5Rs

1 Kg Garlic = 0.25 Rs

Total Weight = 10Kg

Total Cash = 10Rs

To Find:

How much of each vegetables should be bought.

Solution:

Let amount of Potato bought = P Kg

Let amount of Onion bought = N Kg

Let amount of Garlic bought = G Kg

P + N + G = 10

4P + 0.5N + 0.25G = 10

Each terms in these two expressions must be a wholle number.

0.5N should be whole number = > N is an even number.

N can be 0, 2, 4, 6, 8, 10.

4P < 10

P can be 0, 1, 2.

0.25G should be a whole number :

G is a multiple of 4 : 0, 4, 8.

Let P = 1 ,

N + G = 9

0.5N + 0.5G = 0.5x9 = 4.5

0.5N + 0.25G = 6

Gives G as a negative number. Hence take P = 2

N + G = 8

0.5N + 0.5G = 4

0.5N + 0.25G = 2

0.25G = 2

G = 8

Therefore N = 0.

Amount of Potato bought is 2Kg, amount of Oninon bought is 0Kg and amount