potato kg 4 and onion 1 kg 50 paisa and garlic kg 25 paisa how we buy 10 kg in 10 rupees.. please answer..
Answers
Given:
1 kg Potato = 4Rs
1 Kg Onion = 0.5Rs
1 Kg Garlic = 0.25 Rs
Total Weight = 10Kg
Total Cash = 10Rs
To Find:
How much of each vegetables should be bought.
Solution:
Let amount of Potato bought = P Kg
Let amount of Onion bought = N Kg
Let amount of Garlic bought = G Kg
- P + N + G = 10
- 4P + 0.5N + 0.25G = 10
Each terms in these two expressions must be a wholle number.
- 0.5N should be whole number = > N is an even number.
- N can be 0, 2, 4, 6, 8, 10.
- 4P < 10
- P can be 0, 1, 2.
- 0.25G should be a whole number :
- G is a multiple of 4 : 0, 4, 8.
Let P = 1 ,
- N + G = 9
- 0.5N + 0.5G = 0.5x9 = 4.5
- 0.5N + 0.25G = 6
Gives G as a negative number. Hence take P = 2
- N + G = 8
- 0.5N + 0.5G = 4
- 0.5N + 0.25G = 2
- 0.25G = 2
- G = 8
Therefore N = 0.
Amount of Potato bought is 2Kg, amount of Oninon bought is 0Kg and amount of Garlic bought is 8Kg.
Answer:
Step-by-step explanation:
1 kg Potato = 4Rs
1 Kg Onion = 0.5Rs
1 Kg Garlic = 0.25 Rs
Total Weight = 10Kg
Total Cash = 10Rs
To Find:
How much of each vegetables should be bought.
Solution:
Let amount of Potato bought = P Kg
Let amount of Onion bought = N Kg
Let amount of Garlic bought = G Kg
P + N + G = 10
4P + 0.5N + 0.25G = 10
Each terms in these two expressions must be a wholle number.
0.5N should be whole number = > N is an even number.
N can be 0, 2, 4, 6, 8, 10.
4P < 10
P can be 0, 1, 2.
0.25G should be a whole number :
G is a multiple of 4 : 0, 4, 8.
Let P = 1 ,
N + G = 9
0.5N + 0.5G = 0.5x9 = 4.5
0.5N + 0.25G = 6
Gives G as a negative number. Hence take P = 2
N + G = 8
0.5N + 0.5G = 4
0.5N + 0.25G = 2
0.25G = 2
G = 8
Therefore N = 0.
Amount of Potato bought is 2Kg, amount of Oninon bought is 0Kg and amount