Question

Potential difference across resistor, inductor and capacitor at t = 1 is VR 4V, V. = 6V and Vc = 3V respectively then potential difference of source at t= 1 sec is ​

Answer 1

Answer:

The potential difference of source is 6.557 V

Explanation:

Given that,

 Potential difference across the resistor, $V_R$ = 4V

 Potential difference across the inductor, $V_L$ = 6V

 Potential difference across the capacitor, $V_C$ = 3V

∴  Potential difference across the source,

                             $V=\sqrt{V_R^2+\left(V_L^2-V_C^2\right)}$         (∵ $V_L > V_C$)

                             $V=\sqrt{4^2+\left(6^2-3^2\right)}$

                             $V=\sqrt{4^2+\left(6^2-3^2\right)}$

                             $V=\sqrt{43}=6.557V$