Question

Potential difference between two given point 5cm apart is 20 volt what is the value of electric field

Answer 1

The Electric field between two plates is given by E=VdE=Vd, where V is the potential difference in volts and d is the distance between the plates.

Given V=10VV=10V and d=5cmd=5cm, E=VdE=Vd=105×10−2=105×10−2 = 200 N/C

 

If the space between two plates of a capacitor is filled with liquid of dielectric constant K, the capacitance of the capacitor: