Physics, asked by bleh123456789, 6 days ago

potential difference of 24 kV maintains a downward-directed electric field between two horizontal parallel plates separated by 1.8 cm in vacuum. Find the charge on an oil droplet of mass 2.2 × 10-13kg that remains stationary in the field between the plates

Answers

Answered by akashsubramanyam3
1

Answer

The correct answer is 1.6 x 10^-18 C .

Explanation:

A potential difference of 24 kV maintains a downward-directed electric field between two horizontal parallel plates separated by 1.8 cm in vacuum. Find the charge on an oil droplet of mass 2.2 x 10^-13 kg that remains stationary in the field between the plates. The correct answer is 1.6 x 10^-18 C .

Answered by LyftCalculator
1

Answer:

1.62*10^-18

Explanation:

F(E)=mg,

E*q=mg.

E=V/d

Hence: q*V/d=mg

Solve for q

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