Question

Potential difference of 6V is applied across a conductor of length 0.12m.find its drift velocity if its electron mobility is 5.6×10^-6m^2v^-1s^-1

Answer 1

Answer:

drift velocity i defined as v= mobility * electric field so

drift velocity in this case is v= 5.6x 16 x 6/0.12(electric field is V/d)

Answer 2

Concept:

Drift Velocity is equal to mobility times Electric field and Electric field is potential difference per unit length.

Given:

Potential difference (V) = 6 V

Length of conductor (L) = 0.12 metre

Mobility (μ) = 5.6 × 10⁻⁶ m²V⁻¹s⁻¹

Find:

Drift Velocity Vd

Solution:

As Drift Velocity is equal to mobility times Electric field

Vd = μ × E   ---1)

and as, Electric field is potential difference per unit length

E = V / L   ---2)

from equation 1 and 2

Vd = μ × (V / L)

We have given value as

Mobility (μ) = 5.6 × 10⁻⁶ m²V⁻¹s⁻¹

Potential difference (V) = 6 V

Length of conductor (L) = 0.12 metre

Putting all the values in formula

Vd = 5.6 × 10⁻⁶ × (6 / 0.12) m/s

Vd = 5.6 × 10⁻⁶ × 50 m/s

Vd = 280 × 10⁻⁶ m/s

Vd = 2.80 × 10⁻⁴ m/s

Hence the Drift velocity is 2.80 × 10⁻⁴ m/s.

#SPJ3