potential difference of a electric bulb is 12V . the current through the electric bulb is to 2A. find the Resistance options 6 ohm 0.16 ohm 32 ohm 0.32 ohm
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Potential Difference ( V ) = 12 V
Electric Current ( I ) = 2 A
From Ohm's Law, V = I*R => R = V/I
R = V / I = 12/2 = 6 Volt/Ampere = 6 Ω
Hence, the resistance of the bulb is 6 Ω.
Therefore, Option(A) is correct.
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