Physics, asked by akanshtomar2002, 1 year ago

Potential due to system of charges ​

Answers

Answered by Anonymous
3

Answer:

First of all , Let's know what Potential is ?

  • Potential :- At any point in an electric field, it's the amount of work done by an external agent against electric forces in moving a unit positive charge from Infinity to that point Without changing it's Kinetic Energy.

Therefore,

The potential due to a Continuous system of charges is given by,

  •    \large \boxed{\large \bold \red{\int k \frac{dq}{r} }}

Now,

For different system of charges,

Potential is also different.

For Example,

Potential due to a uniformly charged ring on its axis is

  •    \large   \boxed { \bold \pink{\frac{kq}{ \sqrt{ {r}^{2} +  {x}^{2}  } } }}

Potential due to a uniformly charged disc on its axis is

  •   \large \boxed{ \bold \pink{\frac{2k \sqrt{ {r}^{2}  +  {x}^{2}  } - x }{ {r}^{2} } }}
Answered by Anonymous
0

 \huge{ \underline{\underline{ \fcolorbox{white}{pink}{\sf{Answer :-}}}}}

First of all , Let's know what Potential is ?

Potential :- At any point in an electric field, it's the amount of work done by an external agent against electric forces in moving a unit positive charge from Infinity to that point Without changing it's Kinetic Energy.

Therefore,

The potential due to a Continuous system of charges is given by,

 \: \large \boxed{\large \bold \pink{\int k \frac{dq}{r} }} </p><p>

Now,

For different system of charges,

Potential is also different.

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