Chemistry, asked by misssakshi4834, 11 months ago

Potential energy -27.2 ev in second orbit of he+ ions then calculate double of total energy in first excited state of hydrogen atom

Answers

Answered by yenula
0

Answer:

Energy = -13.6Z²/n²

= -13.6 * 4/4

= -13.6 eV

Radius = 0.529 n²/Z Å

= 0.529 * 4/2

= 1.058 Å

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