Question

Potential energy is - 27.2 eV in second orbit of
He then calculate, double of total energy in first
excited state of hydrogen atom :-
(1) - 13.6 eV
(2) – 54.4 eV
(3) - 6.8 eV
(4) - 27.2 eV​

Answer 1

Answer:

None of These

Explanation:

The difference between the potential energy and the total energy is just a (-).

Thus, the potential energy of hydrogen atom in second orbit (first excited state). is 27.2eV.

∴The double of the total energy in first excited state of hydrogen atom is 54.4eV.

But, unfortunately the options does not contain the correct answer.