Chemistry, asked by khushigarg4610, 10 months ago

Potential energy is -27. 2eV in second orbit of helium then calculate double of total energy in first excited state of hydrogen atom

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Answered by UrvashiBaliyan
23

Potential energy is -27. 2eV in second orbit of helium then calculate double of total energy in first excited state of hydrogen atom

Answered by nrathour769
18

If potential energy in ground state is taken to be zero, then 1) Potential ... Total energy of an electron in an orbit is given by. En = -13.6 / n2 eV where n indicates the orbit number.

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