Physics, asked by vedprakash6597, 1 year ago

Potential energy of a 1kg particle free to mve along x axis is given by v(x)={x^4/4-x^2/2} joule.

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Answered by TheDivyansh
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Tne potential energy if a 1kg particle free to move along the x -axis is given by V (x)=(x^4/ 4-x^2/2)The total mechanical energy of the ...

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