Potential energy of a particle at position x is given by u=x^2-5x
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Answered by
8
Answer:
Potential is minimum at x=2.5
Minimum Potential = -6.25
Explanation:
Given that,
....(I)
On differentiate of u
Now,
Then,
Now, double derivative is
At x = 2.5, double derivative is positive.
So, put the value of x in equation (I)
Hence, potential is minimum at x=2.5 Minimum Potential = -6.25
Answered by
3
"x=2.5
As we know that a particle is said to be in equilibrium if net force acting on the particle is zero .
we can also go through this formula
For Force=0 we have to make
now put the value in first derivative i.e 2X-5=0 .
x=2.5 ans"
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