Question

Potential energy of ground state hydrogen atom is 0 then energy in 1 excited state

Answer 1

total energy of any level in Hdrogen atom is E = -13.6/n2

E (ground state) = -13.6ev

E(first exited state) = -13.6/4 ev

potential of ground state = -27.2ev

if potential of ground state is 0 then we have to add +27.2 , by this method we

can make ground state potential 0 ...

now add this potential to  energy of  each state this will give the final energy of that state ...

E(first exited state) = -13.6/4 + 27.2 = 23.8ev