Question

Potential field v=50x^2yz +20y^2 volts in free space find potential v at P(1,2,3)

Answer 1

Answer:

30 40 56 hope u get it okk

Answer 2

Answer:

The potential at the point (1,2,3) is 380 volt

Explanation:

Given that,

The equation of potential field in free space is

$V = 50 {x}^{2} yz + 20 {y}^{2}$

We are required to find the potential.at the point (1,2,3) for that we directly substitute the values of x,y and z in the equation of potential field.Therefore we get,

$V_{(1,2,3)}=50( {1}^{2} )(2)(3) + 20 ({2}^{2} ) \\ = 380 \: volt$

Therefore,the potential at the point (1,2,3) is found to be 380 volt

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