Question

potential of the point B in the circuit below is (1)5V. (2)6V. (3)7V. (4)8V​

Answer 1

see attachment

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Answer 2

Hence the potential of point B in the circuit is 7 V

Explanation:

In loop ABCD

Current "I" = ( 1 + 2 + 3 + 1 + 2) = 12 - 3

Current "I" (9) = 9

I = 1 A

From DAB

I (2 + 1 + 2) = VD + 12 - VB

I (S) = 0 + 12 - VB

S = 0 + 12 0 VB

VB = 12 - 5 = 7 V

Hence the potential of point B in the circuit is 7 V