Pove that Cos 60° Cos30°-Sin60° Sin30°=Cos90°
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Answer:
LHS=Cos 60° Cos30°-Sin60° Sin30°
now putting the value of the trigonometric variables
=Cos 60° Cos30°-Sin60° Sin30
=1/2×√3/2-√3/2×1/2
=√3/4-√3/4
=0
=cos90°
=RHS
hence proved
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