Question

power dissipated across rhe resistor x is​

Answer 1

The diagonal resistors are in series.
3 Ohms + 3 Ohms = 6 Ohms
3 Ohms + 3 Ohms = 6 Ohms
The fifth resistor is parallel with the 
two 6 Ohms series combinations.
1/Re = 1/6+1/6+1/3 =1/6+1/6+2/6 = 4/6
1/Re = 2/3
Re = 1.5
Total current = 1.5V/1.5Ohms = 1 Ampere
.5 Amperes through 6 Ohms parallel 6 Ohms
.5 Amperes through 3 Ohms
Each 6 Ohm series combination carries .25 Amperes.
Power = I²×R = (.25)²×3 = .1875 Watts
(Answer: (2) 0.187 W)


Hope this will help you.
Please mark me as a brain list.