Question

power dissipated in the following circuit is​

Answer 1

Answer:

16W is the answer.

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Answer 2

Answer:

option A 32 W

Explanation:

The above pic is the transformation of the circuit

after the calculation of equivalent resistance.

In the fig 1. the 6 ohm resistors in parallel are combined following the formula R1×R2/R1+R2

Similarily, the 8 ohm resistors.

In fig. 2 the 3ohm resistor, 4ohm resistor and 1 ohm resistor are in series combination so the equivalent resistance is 8 ohm following the formula R1+R2+R3+.........Rn

Now V=16 V

R= 8 ohms

According to ohm's law, V=IR

I= V/R

=>16/8

=>2 A

Hence I = 2A

We know that

$p = {i}^{2} r$

$so \: p = {2}^{2} \times 8 \\ = 4 \times 8 \\ = 32 \: w$

Hence the power dissipated in the circuit is 32 W.

which is option A.

Thank you......

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