Math, asked by krishnaarav3, 2 months ago

power
How much time will be required
to perform 260 J of work at the
rate of 13 W?​

Answers

Answered by jaymodha10965
16

Step-by-step explanation:

__________________________________

Formulas to remember:-

1) P=w/t

2) t=p/w

____________________________________

:-Initial condition

Work done=260Joules

Power required=13Watt

___________________________________

There is no final condition hence time required is:-

p =  \frac{w}{t}

t =  \frac{w}{p}

t =  \frac{260}{13}  = 20sec

Hence time required is 20 seconds.

Please do like to my answer.

Answered by aryan6765
2

Answer:

Step-by-step explanation:

__________________________________

⚡Formulas to remember:-

1) P=w/t

2) t=p/w

____________________________________

:-Initial condition

Work done=260Joules

Power required=13Watt

___________________________________

There is no final condition hence time required is:-

p = \frac{w}{t}p=

t

w

t = \frac{w}{p}t=

p

w

t = \frac{260}{13} = 20sect=

13

260

=20sec

Hence time required is 20 seconds.

Please do like to my answer.

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