Question

Power is the rate of work done. Power indicates the efficiency of a machine.
a. Calculate the power if Machine X does the work of 2100 Joules for 70 seconds.
b. If Machine Y does the work of 3500 Joules for 50 seconds, which of the two machines has more power?
pls help me

Answer 1

Answer:

2100÷ 70 = 30 joules/sec.

3500÷50= 70 joules/sec.

machine x has more power.

Explanation:

1. power = work done per unit time.
2. power = work done ÷ time
3. In case of machine X power os 30 joules per sec or 30 watts (watt is unit of power).
4. in case of machine Y power is 70 joules per second or 70 watts.
5. as machine Y can do more work per unit time machine Y is more efficient