Physics, asked by adithyaadithya938, 1 month ago

. Power of a 200V electrical device is 500W. a) Calculate the electrical current through this device. b) What will be the amperage of the fuse? c) Find the resistance of the device.​

Answers

Answered by ibanivanshika
1

Answer:

20-ampere fuse should blow when the current through it exceeds 20 amps. In this case, let us consider a device of power 5 kW, that is, 5000 W and 200 V. The current through the appliance is given as I=P/V. =25A

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