Question

Power of a bulb is given by the formula​

Answer 1

Answer:

Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (emf = voltage).

Answer 2

Power = force multiplied by speed (velocity) p=F xv.

Explanation:

• Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: inflate, international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (e m f = voltage).
• To find the kilowatt-hours your light bulb consumes per month, multiply the kilowatt use by the number of hours it's on each month. The incandescent bulb uses 0.06 kW of power and is on for 180 hours a month. Its energy usage is (0.06 kW * 180 hours/month) = 10.8 kilowatt-hours per month.
• In an electric circuit, electrical energy is continuously converted into other forms of energy. For example, when a current flows in a conductor, electrical energy is converted into thermal energy within the conductor.