Question

power of the lens is -1.50. find the focal length of the lens and state its nature

Answer 1

Power=1/focal length(in m)
f=1/P→f=1/-1.5
=0.66m
Nature= Concave lens
Image will be virtual and erect

Answer 2

Please check the answer once more...


Edit:Nature of the image formed is virtual erect and diminished.....