Question

Power of the only force acting on a particle of mass m = 1 kg moving in straight line depends on its
velocity as P = v^2 where v is in m/s and P is in watt. If initial velocity of the particle is 1 m/s, then the
displacement of the particle in ln2 second will be
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Answer 1

Answer:

dW = Fdx

dW = Madx  

dW =  Mvdv/dx  * dx

 dW = M * a√x * a/2√x dx

dW = M * a^2/2 dx

Integerating both sides with limits x =0 to x = d we get,

W = (Ma^2/2)d – 0

    = (Ma^2/2)d Joule.

Answer 2

Hello dear

I am very sorry i don't know the answer