Question

Power
$p = \frac{a - {x}^{2} }{bt}$
, where x is the distance and t is the time, the dimensions of b are ?!

Units and measurements.
$i \: need \: solution \: with \: steps$
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Answer 1

Answer:

m^-1T^2

Explanation:

apply principle of homoginity

same dimensionas are added and subtracted

see attachment

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Answer 2

GIVEN EXPRESSION : p = a-x²/bt

✒️ Dimension of p = ML^2T^(-3)

✒️ Dimension of x² = L²

✒️ Dimension of t = T

Now, Dimension of a = Dimension of x² = L²

Also, Dimension of p = Dimension of (a-x²/bt)

i.e., ML^2T^(-3) = L²-L²/b.T

or, b = (L²-L²)/(ML²T^-2) = L²/ML²T^(-2) = M^(-1)T²

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