Power usage is measured in kilowatt-hours, kWh. After 7 a.m., the power usage on a college campus increases at a rate of 21% per hour. Prior to 7 a.m., 15,040 kWh have been used. The university has a daily goal to keep their power usage less than or equal to 100,000 kWh.
PLEASE HELP!!
Which of the following inequalities can be used to determine the number of hours, t, after 7 a.m. when the power usage on campus will be less than or equal to 100,000?
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Is not a very difficult question
tylerjstamey58:
im not very intelligent
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After 7 a.m., the power usage on a college campus increases at a rate of 21% per hour.
t be the number of hours
the power usage increases at a rate of 21% per hour
21% = 0.21, constant rate = 0.21 . So slope = 0.21
Prior to 7 a.m., 15,040 kWh have been used.
At 7.am , power used = 15,040kWh. so our y intercept is 15,040
We use slope intercept form y=mx+b
slope m = 0.21 and b = 15040
power usage , y = 0.21 t + 15040
The university has a daily goal to keep their power usage less than or equal to 100,000 kWh
Power usage is less than or equal to 100,000
So inequality becomes 0.21t + 15,040 <= 100,000
t be the number of hours
the power usage increases at a rate of 21% per hour
21% = 0.21, constant rate = 0.21 . So slope = 0.21
Prior to 7 a.m., 15,040 kWh have been used.
At 7.am , power used = 15,040kWh. so our y intercept is 15,040
We use slope intercept form y=mx+b
slope m = 0.21 and b = 15040
power usage , y = 0.21 t + 15040
The university has a daily goal to keep their power usage less than or equal to 100,000 kWh
Power usage is less than or equal to 100,000
So inequality becomes 0.21t + 15,040 <= 100,000
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