Question

pozzzz solve the problem.... ​

Answer 1

$\huge\underline{\overline{\mid{\bold{ \orange{Given}}\mid}}}$

• Height (h) of the cylindrical part = 2.1 m

• Diameter of the cylindrical part = 4 m

• Radius of the cylindrical part = 2 m

$\huge\underline{\overline{\mid{\bold{ \blue{To \: Find}}\mid}}}$

• Area of the canvas used for making the tent

• the cost of the canvas of the tent at the rate of Rs 500 per m²

$\huge\underline{\overline{\mid{\bold{ \green{Solution}}\mid}}}$

• Area of canvas used = CSA of conical part + CSA of cylindrical part

$\tt \implies \pi rl + 2\pi rh$

$\tt\implies \pi \times 2 \times 2.8 + 2\pi \times 2 \times 2.1$

$\tt\implies 2\pi \bigg[2.8 + 2 \times 2.1 \bigg] = 2\pi \bigg[2.8 + 4.2 \bigg] = 2 \times \frac{22}{7} \times 7</p><p></p><p>$

$\tt\implies 44 {m}^{2}$

• Cost of 1 m² canvas = RS 500

• Cost of 44 m² canvas = 44 × 500 = 22000

Therefore, it will cost Rs 22000 for making such a tent.

Answer 2

From the question, we know that

The diameter = D = 4 m

| = 2.8 m (slant height)

The radius of the cylinder is equal to the radius of the cylinder

So, r = 4/2 = 2 m

Also, we know the height of the cylinder (h) is 2.1 m

So, the required surface area of the given tent = surface area of the cone (the top) + surface area of the cylinder(the base)

= trl + 2rrh

= Ter (1+2h)

Now, substituting the values and solving it we get the value as 44 m^2

.. The cost of the canvas at the rate of Rs. 500 per m^2 for the tent will be

= Surface area x cost/ m^2

= 44 x 500

=22000

Hope it helps!