Question

pपी प्लस 2p स्क्वायर प्लस 10p स्क्वायर प्लस 5p4 - 8 ​

Answer 1

Answer:(i) given , polynomial is

p(x)=10−4x2−3

On putting x=0.1 -2 respectivel,y in Eq .(i) we get

p(o)=0(0)−4(0)2−3

=0−0−3=−3

p(1)=10(1)−4(1)2−3

=10−4−3=10−7=3

andp(−2)=10(−2)−4(−2)2−3

=−20−4×4−3

=−20−16−3=−39

Hence , the values of p(0) ,p(1) and p(-2) are respecively ,−3,3and−39.

(ii) Given ,polynomial is p(y)=(y+2)(y−2)

On putting =0,1 and -2 , respectively in Eq,(i) , we get

p(0)=(0+2)(0−2)=−4

p(1)=(1+2)(1−2)

=3×(−1)=−3

and p(−2)=(−2+2)(−2−2)

=0(−4)=0

Hence , the values of p(0) , p(1) and p(-2) respecively , -4, -3 and 0.

Step-by-step explanation: PLS SUBSCRIBE TO MY YOUTUBE CHANNEL

TECH SCORCHING