Question

pplleessee aannsswweerr mmee ​

Answer 1

which standard question

Answer 2

TOTAL NO. OF OBSERVATIONS=300


So first . probability of having MOTE than 4=
$\frac{no.of \: times \: 4.5and6 \: came}{total \: no \: of \: observations}$
$= \frac{60 + 53 + 60}{300}$
$= \frac{173}{300}$
and
p(less than 3)
$\frac{no \: of \: times \: 3 \: \: 2 \: \: and \: 1 \: \: came}{total \: no \: of \: observations}$
$= \frac{55 + 30 + 42}{300}$
$= \frac{127}{300}$