Question

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Answer 1

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Answer 2

Answer:

ASA CRITERION

Step-by-step explanation:

RT = RS

thus

$\angle \: TRS= \angle \: TSR \\ (angles \: opposite \: to \: equal \: sides \: are \: equal) \\ \\ \angle1 = \angle4 \\ (vertically \: opposite \: angles) \\ \\ \angle1 = 2\angle2 (given)\\ \angle4 = 2\angle3 (given)\\ \\ 2\angle2 = 2\angle3 \\ \angle2 = \angle3\\ \angle \: TRS - \angle2 = \angle \: TSR- \angle3 \\ \\ \angle \: TRB= \angle \: TSA \\ (when \: equals \: are \: subtracted\\ \: from \: equals \: remaining \: are \: equals)$

Now angle T is common in both the triangles.

RT=RS (given)

Thus by ASA CRITERION OF CONGRUENCY

$\triangle \: RBT \cong \: \triangle \: SAT$

Hope it helps you.