ppzz answer my question
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Sin30° = 1/2
Cos60° = 1/2
Tan45° = 1
And,
Cot60° = 1/√3.
Given : X = 20°
Substitute X = 20° in ,
12 Sin 3X/2 × Cos 3X + 5 × Tan ( 2X + 5°) - 3 Cot² 3X.
12 × Sin 3 × 20°/2 × Cos 3×20° + 5 × Tan ( 2×20°+5)- 3 Cot² 3 × 20°.
12 Sin30° × Cos60° + 5 × Tan ( 40° + 5° ) - 3 Cot²60° .
12 × 1/2 × 1/2 + 5 × Tan45° - 3 × (1/√3)²
12/4 + 5 + 1 - 3 × 1/3
3 + 5 + 1 - 1
3 + 5
8
Cos60° = 1/2
Tan45° = 1
And,
Cot60° = 1/√3.
Given : X = 20°
Substitute X = 20° in ,
12 Sin 3X/2 × Cos 3X + 5 × Tan ( 2X + 5°) - 3 Cot² 3X.
12 × Sin 3 × 20°/2 × Cos 3×20° + 5 × Tan ( 2×20°+5)- 3 Cot² 3 × 20°.
12 Sin30° × Cos60° + 5 × Tan ( 40° + 5° ) - 3 Cot²60° .
12 × 1/2 × 1/2 + 5 × Tan45° - 3 × (1/√3)²
12/4 + 5 + 1 - 3 × 1/3
3 + 5 + 1 - 1
3 + 5
8
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