Question

PQ + 5r the whole square using identities​

Answer 1

The solution is $P^{2} Q^{2} +10PQr+25r^{2}$

Explanation:

The expression is $(\mathrm{PQ}+5 \mathrm{r})^{2}$

We need to solve the expression using the identity $(a+b)^{2}=a^{2}+2 a b+b^{2}$

where $a=PQ$ and $b=5r$

Expanding the expression, we have,

$(\mathrm{PQ}+5 \mathrm{r})^{2}=(PQ)^{2} +2(PQ)(5r)+(5r)^{2}$

Simplifying the expression, we get,

$(\mathrm{PQ}+5 \mathrm{r})^{2}=P^{2} Q^{2} +10PQr+25r^{2}$

Thus, the solution of the expression $(\mathrm{PQ}+5 \mathrm{r})^{2}$ is $P^{2} Q^{2} +10PQr+25r^{2}$

Learn more...

1. brainly.in/question/5319883

2. brainly.in/question/3062963

Answer 2

Answer:

the answer is p²q²+10pqr+25r