PQ and PR are tangents to a circle with centre O such that PQ is 7 cm and angle OPR = 60° . Find the length of chord QR
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we know that line from center bisects the chord therefore pX =XQ
.: PQ=pX+Xp
7√3/2+7√3/2=7√3
.: PQ=pX+Xp
7√3/2+7√3/2=7√3
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hope it helps you plz mark as the brainliest answer....
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