PQ and PR are the two chords of a circle of radius r. If the perpendiculars drawn from the
centre of the circle to these chords are of lengths a and b, PQ = 2PR, then prove that:
b2=2/4+3r2/4
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Answer: In the figure above, AB and AC are the chords of the circle with center O and radius r.
such that AB = 2AC
and length of the perpendiculars OM and ON are a and b respectively.
since the perpendicular from the center to the chord bisects the chord.
AM = AB/2 and AN = AC/2
in the right angled triangle ONA, using pythagoras thm.
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