Question

PQ and RQ are chords of a circle equidistant from centre. Prove that the

diameter passing through Q bisects ∠PQR and ∠PSR.​

Answer 1

Answer:

Figure of this question is attached !!

Step-by-step explanation:

PROOF :

OP = OR ( equal radii )

OQ = OQ ( common )

PQ = RQ ( equal chords )

OPQ = congruent = ORQ ( by SSS )

$< pqo \: = < \: rqo \: ( \: cpct \: )$

Therefore,

Q is the bisector of the angle PQR .

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