Question

PQ and RS are intersect each other at a point O. If anglePOR : angleROQ = 5:7. Find all the angles.

Answer 1

hence the angle are 105,75,105,75

Answer 2

Answer:

∠POR = ∠QOS = 75°( vertically opposite angles)

∠ ROQ = ∠POS = 105° ( vertically opposite angles)

Step-by-step explanation:

Given :  ∠POR : ∠ROQ = 5 : 7

Let ∠POR = 5x & ∠ROQ = 7x

By Linear pair axiom,

∠POR + ∠ROQ = 180°

5x + 7x = 180°

12x = 180°

x = 180/12

x = 15°  

so,

∠POR = 5x = 5 × 15 = 75°

∠ROQ =  7x = 7 × 15 = 105°

then,

∠POR = ∠QOS = 75°( vertically opposite angles)

∠ ROQ = ∠POS = 105° ( vertically opposite angles)

Step-by-step explanation:

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