PQ and RS are respectively the smallest and longest sides of a quadrilateral PQRS.Show that Angle P > angle R
Anupkashyap:
can you use trigonometry?????
Answers
Answered by
7
since angle opposite to larger side is greater therefore <P is greater than <R
Answered by
0
Answer:
PQ is the smallest sides of the quadrilateral and RS is the longest sides of the quadrilateral
Step-by-step explanation:
Given: PQRS is a quadrilateral
To find: ∠P> ∠R
Solution:
PQRS is a quadrilateral. PQ is its longest side and RS is its shortest side.
∠P> ∠R
Join PR and QS.
: In ΔPQR
PQ is longest side
PQ > QR
In ΔPSR
RS is the shortest side
PS > RS
Therefore ,
∠P> ∠R
Angle with larger side has the greater angle
#SPJ3
Attachments:
Similar questions