Pq and rs are two equal and parallel line segments. Any point m not lying on pq or rs is joined to q and s and lines through p parallel to qm and through r parallel to sm meet at n . Prove that line segments mn and pq equal and parallel to each other
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Answered by
19
Answer:
PQ=RS and MN ║ QM
Angle RPN = Angle SQM
PR = QS
Δ PRN≅QSM
PN = QM and RN = SM
∵ PN ║ QM and PN = QM
PQMN is a parallelogram
∵RN ║ SM and RN = SM
RNSM is a parallelogram
Thus, PQ = MN and PQ ║ MN
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Step-by-step explanation:
Answered by
13
Answer:
PQ=RS and MN ║ QM
Angle RPN = Angle SQM
PR = QS
Δ PRN≅QSM
PN = QM and RN = SM
∵ PN ║ QM and PN = QM
PQMN is a parallelogram
∵RN ║ SM and RN = SM
RNSM is a parallelogram
Thus, PQ = MN and PQ ║ MN
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