PQ and RS are two mirrors placed parallel to each other. An incident ray AB
strikes the mirror PQ at B , the reflected ray moves along the path BC and strikes
the mirror RS at C and again reflects back along CD.If PBA 50 then,
Answer the following questions.
a What is the measure ofABC ?
i) 400
ii) 500
iii) 700
iv) 800
b What is the measure ofDCS ?
i) 300
ii) 400
iii) 500
iv) 600
c What is the measure ofBCS ?
i) 1300
ii) 1250
iii) 1100
iv)1200
d What is the measure ofBCR ?
i) 400
ii) 450
iii) 500
iv) 550
e What is the measure of QBC ?
i) 400
ii) 500
iii) 550
iv) 600
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Answered by
0
Answer:
400 see carefully so as you see all places
Answered by
0
Answer:
a. 80 degree. b. 50 degree. c. 130 degree. d. 50 degree. e. 50 degree
Step-by-step explanation:
L ABC= 180-(50+50)=180-100=80 degree
L DCS= 90-40=50 degree(angle of incidence = angle of reflection. we got abc as 80. so, angle of reflection becomes half of 80 that is 40...as the normal is 90 degree)
L BCS= 90+40=130 degree
L BCR=L DCS=50 degree
L QBC= L PBA=50 degree
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