PQ and RS are two parallel chords of a circle on the same side of centre O and radius is 10cm. if PQ=16cm and RS=12cm, find the distance between the chords.
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Step-by-step explanation:
op=oq=or=os=10cm
consider ∆OAQ
OA^2+AQ^2=10^2
OA^2+8^2=100
OA=6
IN ∆OBS
OB^2+BS^2=100
OB=8
AB=Obama
AB=8-6=2
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