PQ and RS are two parallel chords of a circle such that PQ = RS = 12 cm and PQ subtends 65° at the center of the circle, then the angle subtended by RS at the center is _______.
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Answer:
65° at the center of the circle, then the angle
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Given : PQ and RS are two parallel chords of a circle such that PQ = RS = 12 cm
PQ subtends 65° at the center of the circle,
To Find : the angle subtended by RS at the center is _______.
Solution:
Angle subtended by congruent chord/arc of a circle at center are congruent
PQ = RS = 12 cm
Hence Chord PQ ≅ chord RS
as Chord PQ ≅ chord RS
=> ∠POQ ≅ ∠ROS where O is center of circle
=> m ∠POQ = m∠ROS
m ∠POQ = 65°
=> m∠ROS = 65°
the angle subtended by RS at the center is 65°
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