PQ and RS are two parallel chords of a circle such that PQ = RS = 12 cm and PQ
subtends 65° at the center of the circle, then the angle subtended by RS at the center
is _______.
a) 180°
b) 130°
c) 65°
d) 32.5°
Answers
Answer:
65 degree is the answer because equal chord substend equal angle at center
Given : PQ and RS are two parallel chords of a circle such that PQ = RS = 12 cm
PQ subtends 65° at the center of the circle,
To Find : the angle subtended by RS at the center is _______.
a) 180°
b) 130°
c) 65°
d) 32.5°
Solution:
Angle subtended by congruent chord/arc of a circle at center are congruent
PQ = RS = 12 cm
Hence Chord PQ ≅ chord RS
as Chord PQ ≅ chord RS
=> ∠POQ ≅ ∠ROS where O is center of circle
=> m ∠POQ = m∠ROS
m ∠POQ = 65°
=> m∠ROS = 65°
the angle subtended by RS at the center is 65°
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