PQ and Rs are two parallel chords of a circle whose Centre is O and radius is 10 centimetre if PQ equal to 16 cm and Rs equal to 12 cm find the distance between PQ and Rs, if they lie
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Answer:
d = distance from centreto Centre of the chord
r=radius
C-length of chord
d=vr2-(c/2)^2
Step-by-step explanation:
.d1=v10^2-8^2 = 6cm
d2=v10^2-6^2 = 8cm
same side=8-6=2cm
oppside = 8 +6=14 cm
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