Question

PQ and RS intersect at O. Given POS = (2x + 30)°and ROQ = (3x - 10)°
Find x?​

Answer 1

Answer:

x°=40°.

Step-by-step explanation:

Given:

PQ intersect at O.

Angle POS=(2x+30)°

Angle ROQ=(3x-10)°.

Here, angle POS=angle ROQ [Since, vertically opposite angles are equal]

=>2x+30=3x-10

=>30+10=3x-2x

=>x=40.

Hence, x°=40°.