PQ and RS intersect at O. If POS=2x-15 and ROQ=x+30. then find the value of POR
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Answer:
135°
Step-by-step explanation:
PQ - a horizontal line
RS - a vertical line
intersect both
the point of intersection is O
then,
top left corner is angle POR
top right corner is angle ROQ
bottom left corner is angle POS
bottom right corner is angle QOS.
therefore
angle POS is vertically opposite of angle ROQ.
so 2x-15= x+30
simplify
x= 45°
now we have to find angle POR so it is a linear pair. so 180°-45° = 135°
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