Question

PQ has endpoints at P (-5,4) and Q (7,-5) what is the length of PQ (Simplify your answer)

Answer 1

Answer:

Given : Here PQ is a line where P

and Q are its coordinates.

Where P (x1,y1) = -5,4

Q (x2,y2) = 7,-5

To find : length of PQ

Solution : here

Lenght PQ = √( x1 -x2)² + (y1 - y2)²

= √(-5-7)² + (4+5)²

= √-12² + 9²

= √144+81

= √225

=15 unit

Answer 2

The length of PQ = 15 unit

Given :

PQ has endpoints at P (-5,4) and Q (7,-5)

To find :

The length of PQ

Formula :

For the given two points ( x₁ , y₁) & (x₂ , y₂) the distance between the points

$= \sf{ \sqrt{ {(x_2 -x_1 )}^{2} + {(y_2 -y_1 )}^{2} } }$

Solution :

Step 1 of 2 :

Write down the given points

Here the given points are P (-5,4) and Q (7,-5)

Step 2 of 2 :

Find the length of PQ

The length of PQ

$\displaystyle \sf{ = \sqrt{ {(7 - ( - 5))}^{2} + {( - 5 - 4)}^{2} } } \: \: unit$

$\displaystyle \sf{ = \sqrt{ {(7 + 5)}^{2} + {( - 5 - 4)}^{2} } } \: \: unit$

$\displaystyle \sf{ = \sqrt{ {(12)}^{2} + {( - 9)}^{2} } } \: \: unit$

$\displaystyle \sf{ = \sqrt{ 144 + 81} } \: \: unit$

$\displaystyle \sf{ = \sqrt{ 225} } \: \: unit$

$\displaystyle \sf{ = 15} \: \: unit$

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