Question

PQ is a chord of a circle and PT is a tangent at P such that angle q t t is equal to 60 then find angle prq

Answer 1

PQ is a chord of a circle with center O. Also, ∠QPT = 60°.

let x be the point on the tangent PT.

Now, ∠QPT + ∠QPX = 180° [Linear pair]

⇒ ∠QPX = 180° - ∠QPT = 180° - 60° = 120°

Again, ∠QPX = ∠PRQ [Alternate segment theorem]

⇒ ∠PRQ = 120