Question

PQ is a chord of a circle and PT is tangent at P such that
Angle QPT = 60 degree, then the measure of Angle PRQ is_____

Please give step by step explanation

Answer 1

Answer:

I willl answerr by 1:00clock

Answer 2

Answer:

120°

Explanation:

Given,

∠QPT=60°

∠OPT= 90°( Radius is perpendicular to the tangent)

So,

∠OPQ=90°- 60°= 30°

OP = OQ( radius of the same circle)

∠OPQ = ∠OQP= 30°

∠POQ= 180 - (30+30)

= 180 - 60°= 120°

∠PAQ= 60°( Angle made by chord to the center is double of angle to the arc)

Now, PARQ is cyclic

So,

∠PAQ+∠PRQ = 180°

=>60°+ ∠PRQ = 180°

=>∠PRQ= 180 - 60 = 120°

Hope it helps ✌️